Question

A stone is thrown horizontally at a velocity of 12.38 m/s from a tree house that is

located 61.8 m above the ground in a beautiful redwood tree. What is the
magnitude of the stone's vertical component of velocity just before it hits the
ground?

Answer 1

34.8 m/s

Step-by-step explanation:

Since we're only interested in vertical velocity we can ignore anything horizontal.

We have the following information (in the vertical direction)

d = 61.8

a = 9.8

vi = 0

vf = ?

The equation combining all these variables is:

`v_f^2 = v_i^2 + 2ad\\v_f^2=0+2(9.8)(61.8)\\v_f^2=1211.28\\v_f=√(1211.28)\\v_f=34.8`