Question

DOES SOMEONE KNOW HOW TO DO THIS???????????????????????????????????????????

Answer 1

`(r\cdot s)(x)=3x^3-3x^2`

`(r+s)(x)=3x^2+x-1`

`(r-s)(-3)=-31`

Explanation:

`(r \cdot s)(x)` means we are multiplying the functions mentioned.

`(x-1)(3x^2)`

Distribute:

`3x^3-3x^2`

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`(r+s)(x)`

This means we are adding the mentioned functions.

`(x-1)+(3x^2)`

No like terms to combine so we are going to rearrange in standard form:

`3x^2+x-1`

----

`(r-s)(-3)`

Replace the x's in both functions with -3, then we will simplify the difference of
`r(-3)` and
`s(-3)`.

`r(x)=x-1`

`r(-3)=-3-1=-4`

`s(x)=3x^2`

`s(-3)=3(-3)^2=3(9)=27`

So now we do -4-27=-31.