Question

An angry mob lynches a phsical teacher after receiving their grades. They throw the physics teacher off a tall building . They throw the physics teacher straight down with a velocity of 20m/s. The teacher falls for 30 seconds before landing on a stack of empty card board boxes . How high was he thrown from?

Answer 1

To calculate the height from which the teacher was thrown, we can use the equations of motion. The teacher was thrown from a height of 4410 meters.

Step-by-step explanation:

To calculate the height from which the teacher was thrown, we can use the equations of motion. The equation to use in this case is:

h = (1/2)gt²

Where:

h is the height

g is the acceleration due to gravity (approx. 9.8 m/s²)

t is the time (30 seconds)

Substituting the given values into the equation, we get:

h = (1/2)(9.8 m/s²)(30 s)²

Simplifying the equation gives us:

h = (1/2)(9.8 m/s²)(900 s²)

h = 4410 m

Therefore, the teacher was thrown from a height of 4410 meters.

Answer 2

5010 m

Step-by-step explanation:

The vertical position of the teacher at time t can be found by using the equation:

`y(t) = h + ut+ (1)/(2)gt^2`

where

h is the initial height

`u = -20 m/s` is the initial velocity (negative since it's downward)

`g=-9.8 m/s^2` is the acceleration of gravity

t is the time

The teacher reaches the ground when y = 0, so the equation becomes

`h=-ut-(1)/(2)gt^2`

Substituting t = 30 s, we find the initial height:

`h=-(-20)(30)-(1)/(2)(-9.8)(30)^2=5010 m`