Answer:
a:
![5.9743*10^(24)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/x6aji8qz58apfpw7zen51lv2s56d6jkddl.png)
b:
![3.00587517*10^(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/a3daznrebzc7nc2zmnb3ces4bl826pdc78.png)
Explanation:
For a:
The combined mass is the totaled mass of all the objects.
So that would be
![(5.9*10^(24))+(7.3*10^(22))+(1.3*10^(21))\\\\(5900+73+1.3)*10^(21)\\\\5974.3*10^(21)\\\\5.9743*10^(24)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jaus6114d4i9en6urqlnzweq9o872a7l1k.png)
For b:
We need to find how many of the moon-Earth-Pluto combinations are needed to match the mass of the sun.
So, we would calculate the following:
![(1.7958*10^(30))/(5.9743*10^(24)) \\\\(1.7958)/(5.9743) *(10^(30))/(10^(24)) \\\\0.300587517 (approx) * 10^(30-24)\\0.300587517*10^(6)\\3.00587517*10^(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ola77j2ilw0r12sawi91ir2ni58t6p9o0x.png)
So it would take approximately
of the moon-Earth-Pluto combos to match the mass of the sun.