Answer:
4.05 m/s
Step-by-step explanation:
We shall represent the different velocity in vector form
Newton runs due north at 3.90 m/s, with respect to standing Daniel .
V_n = 3.9 j
Let Pauli runs with respect to standing Daniel with velocity X .
Then relative velocity of Newton with respect to running Pauli will be
3.9 j - X
Give that
relative velocity of Newton with respect to running Pauli = 1.1 i ( 1.1 due east )
So
3.9 j - X = 1.1 i
X = -1.1 i + 3.9 j .
Magnitude of X
X² = 1.1 ² + 3.9²
X = 4.05 m/s
So Pauli runs with respect to standing Daniel with velocity 4.05 m /s .
Direction will be , west of north at angle θ ,
Tan θ = 1.1 / 3.9