Question

Help please! I need to write 4y =-3x + 12 in standard form, find the y-intercept of the previous equation, as an ordered pair, and find the x-intercept of the previous equation, but I forgot how. I need the answer asap! Thank you!

Answer 1

`-3x+4y=12\\y-intercept: (0,3)\\x-intercept: (-4,0)`

Explanation:

The standard form of a linear equation is
`ax+by=c`, where
`a` ,
`b`, and
`c` are constants in the equation.

Based on the equation you have provided, the standard form would be
`-3x+4y=12`, where
`a=-3, b=4, c=12`.

To find the y-intercept, set
`x=0`.

`-3(0)+4y=12\\0+4y=12\\4y=12\\y=(12)/(4) =3`

Therefore, the y-intercept is
`(0,3)`.

Do the same thing for the x-intercept, but this time with
`y=0`.

`-3x+4(0)=12\\-3x+0=12\\-3x=12\\x=(12)/(-3) =-4`

Therefore, the x-intercept is
`(-4,0)`.