Question

Assume that nextWord is a String variable that has been given a String value consisting entirely of letters. Write some Java code that outputs the message "First half of the alphabet" , provided nextWord precedes "N" in alphabetic ordering. IfnextWord does not precede "N" in alphabetic ordering, the code should output"Second half of the alphabet" . (Note that "N"uses double quotes to produce aString value, as opposed to using single quotes to produce achar value.) '

Answer 1

The code example is given below with explanation in c++ language.

Step-by-step explanation:

Comments will explain what's going on in the code. Below code is already compiled and tested.

#include <time.h>

#include <iostream>

#include <sstream>

using namespace std;

int main(void)

{

//defining start and end time variable

// which will be used to break the infinte loop

time_t endwait;

time_t start = time(NULL);

time_t seconds = 3; // end loop after this time has elapsed

cout<<"Input your number :";

long userNum;

cin>> userNum;

// initializing end time by adding seconds with start time

endwait = start + seconds;

// defining outputString which will concatenate all the

// divisible numbers in loop

string outputString="";

// bool isCompleted will use to check whether our

// loop breaks successfully or time is expired.

bool isCompleted=true;

// iterate loop until it comes to 1. as in loop

// the program already displayed the 1 value.

while (userNum>1)

{

// checking start and end time comparison to

// break the infinite loop after some seconds

if(start >= endwait){

cout<< "Program end never reached.";

isCompleted=false;

break;

}

userNum=userNum/2;

// defining stringstream to convert from long to string

stringstream longToString;

longToString<<userNum;

// concatenating all the values

outputString = outputString + longToString.str()+" ";

// re initializing the start time with current time.

start = time(NULL);

}

// check if while loop breaks successfully then print the

// series of numbers here.

if(isCompleted) {

cout << outputString;

}

return 0;

}