Question

An engineer is designing a process for a new transistor. She uses a vacuum chamber to bombard a thin layer of silicon with ions of phosphorus, each of mass mP = 5.18 × 10-26 kg. The phosphorus ions are doubly ionized, with each phosphorus ion lacking two electrons. The ions start at rest at one end of the vacuum chamber and are accelerated by an electric field over a distance of re = 46 cm before they strike the silicon layer with velocity vP = 180 m/s. Calcultae the average electric field strength, E, across the vacum chamber.

Answer 1

`E=5.7* 10^(-3)\ V/m`

Step-by-step explanation:

Given that

`m_p=5.18* 10^(-26)\ kg`

re= 46 cm

Vp= 180 m/s

We know that

`E=(\Delta V)/(r)`

`\Delta V=(1)/(4)(m_pv_p^2)/(e)`

So

`E=(1)/(4)(m_pv_p^2)/(e.r_e)`

Now by putting the all given values in the questions

`E=(1)/(4)* (5.18* 10^(-26)* 180^2)/(1.6* 10^(-19)* 0.46)`

`E=5.7* 10^(-3)\ V/m`

So the average electric field is
`E=5.7* 10^(-3)\ V/m`.