Answer:
Total membership for a year is $588
Total membership for 5 years is $60
Explanation:
This is an arithmetic sequence of the form:
60, 58, 56, 54 ...
The first term is a = 60
the common difference is d = -2
We need to find the total member cost for a year, that is the sum of all the first 12 terms. We use the formula of sum of arithmetic sequence shown below:
![S_n=(n)/(2)[2a+(n-1)d]](https://img.qammunity.org/2020/formulas/mathematics/high-school/p82o14tt1akmx6szgemiszk1cohd2h7amw.png)
Where
a is first term
n is the number of term [here, 12]
d is common difference
From what we know, we can find:
![S_n=(n)/(2)[2a+(n-1)d]\\S_(12)=(12)/(2)[2(60)+(12-1)(-2)]\\S_(12)=588](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nnmo95kwn0ca2gr4275at07et9lwktri54.png)
Total membership for a year is $588
Now to find this for 5 years, we have to find 5*12 = 60 months.
So S_60, formula and find:
![S_n=(n)/(2)[2a+(n-1)d]\\S_(60)=(60)/(2)[2(60)+(60-1)(-2)]\\S_(60)=60](https://img.qammunity.org/2020/formulas/mathematics/middle-school/eo5fk4qmi9p81xctu5c3gfkz9o4nvto4k4.png)
Total membership for 5 years is $60