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A plane, diving with constant speed at an angle of 42.8° with the vertical, releases a projectile at an altitude of 605 m. The projectile hits the ground 6.71 s after release. (a) What is the speed of the plane? (b) How far does the projectile travel horizontally during its flight? What were the magnitudes of the (c) horizontal and (d) vertical components of its velocity just before striking the ground? (State your answers to (c) and (d) as positive numbers.)

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Final answer:

To find the speed of the plane and the distance traveled by the projectile, we can use the given information and apply trigonometry. The magnitudes of the horizontal and vertical components of the velocity just before the projectile hits the ground can also be determined using trigonometry.

Step-by-step explanation:

To find the speed of the plane, we can use the fact that the speed of the plane is constant. We can divide the altitude of the projectile by the time it takes for it to hit the ground to find the vertical component of the velocity. Using trigonometry, we can then find the speed of the plane.

To find the horizontal distance traveled by the projectile, we can use the time it takes for the projectile to hit the ground and the horizontal component of the velocity to calculate the distance.

The horizontal and vertical components of the velocity just before the projectile strikes the ground can be found using trigonometry. The magnitude of the horizontal component of the velocity will be equal to the initial velocity of the projectile, and the magnitude of the vertical component can be determined using the time it takes for the projectile to hit the ground.

User Rodel Sarate
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Answer:

See them in the pic

Step-by-step explanation:

See them in the pic

A plane, diving with constant speed at an angle of 42.8° with the vertical, releases-example-1
User NameSpace
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