Question

1. Identify the quantity through the use of fundamental dimensions. nRT where: n = amount [mol] R = ideal gas constant [atm L/(mol K)] T = temperature [K] Choose from the following: Energy Correct! Press enter after select an option to check the answer Power Press enter after select an option to check the answer Velocity Press enter after select an option to check the answer Acceleration Press enter after select an option to check the answer Pressure Press enter after select an option to check the answer Force

Answer 1

Energy

Step-by-step explanation:

The easiest way would be to remember that PV=nRT and doing fundamental dimensions on that equation:
`[nRT]=[PV]=[P][V]=ML^(-1)T^(-2)L^3=ML^2T^(-2)`, so the answer is Energy.

This is because we have to remember that P=F/A, and F has dimensions of mass (
`M`) and acceleration (
`L/T^(-2)`) while A has dimensions of longitude squared (
`L^(2)`), which gives
`[P]=ML^(-1)T^(-2)`. Volume has dimensions of
`L^(3)`.

We can use any energy formula to know its dimensions, for example, from the Kinetic Energy we know that it must has dimensions of mass and velocity squared, [E]=
`ML^2T^(-2)`, which is what we got.