Question

Please solve it I will give you 30 points

Answer 1

1.) (2x - 1)(x + 1)

2.) a = 6 ; b = -1

4.a.) x = all rational numbers excluding (-2÷3)

4.b.) x = -1

4.c.) Yes. x = 1÷2

Explanation:

E(x) = (2x - 1)² + (x - 2)(1 - 2x) F(x) = ax²-bx-2

F(1) = 5 ; F(-2) = 20

a-b=7 ; 4a+2b=22

3.Answer) Q(x) = 6x² + x - 2

= 6x² + 4x - 3x - 2

= (3x + 2)×(2x - 1)

Hence verified!

P(x) = E(x) ÷ Q(x)

= (x + 1)÷(3x + 2)

Here, x belongs to,

`( - \infty \: to \: - 2 / 3) union( - 2 / 3 \: to \: \infty )`

Means, except x = -2÷3 , all real numbers are valid excluding complex numbers.

P(x) = (x + 1)÷(3x +2) = 0

= > x = -1

Answer 2

1. (2x^2+x-1)

Explanation:

expanding (2x^2-1)^2. multiplying (x-2) (1-2x)

= 4x^2-4x+1. = x-2x^2-2+4x

= -2x^2+5x-2

(4x^2-4x+1-2x^2+5x-2)

=2x^2+x-1