Answer:
a) P(A) is the probability that a randomly selected American adult has a library card.
P(A/B) is the probability that a randomly selected American adult has a library card, given that he is a male.
P(A/C) is the probability that a randomly selected American adult has a library card, given that she is a female.
b) There is a 36.5% probability that an American adult is a female who owns a library card.
c) There is a 53.68% probability that a randomly selected American adult who owns a library card is a female.
Explanation:
(a) consider the three probabilities: P(A) = .68, P(A|B) = .62, and P(A|C) = .73.
P(A) is the probability that a randomly selected American adult has a library card.
P(A/B) is the probability that a randomly selected American adult has a library card, given that he is a male.
P(A/C) is the probability that a randomly selected American adult has a library card, given that she is a female.
(b) Assuming that half of all Americans are males, what is the probability that an American adult is a female who owns a library card.
There is a 50% probability that an American adult is a male and a 50% probability that an American adult is a female.
There is a 73% probability that an American adult female owns a library card.
So

There is a 36.5% probability that an American adult is a female who owns a library card.
(c) Assuming that half of all Americans are males, what is the probability that a randomly selected American adult who owns a library card is a female?
68% of all american adults have a library card.
In b), we found that 36.5% are american female adults who own a library card.
So

There is a 53.68% probability that a randomly selected American adult who owns a library card is a female.