Question

python A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year.

Answer 1

i_year=int(input(""))

#check leap year

if((i_year % 4 == 0 and i_year % 100 != 0) or (i_year % 400 == 0)):

print("{} is a leap year.".format(i_year))

else:

print("{} is not a leap year.".format(i_year))

Step-by-step explanation:

Answer 2

// program in Python.

#read year

i_year=int(input("Please Enter a year:"))

#check leap year

if((i_year % 4 == 0 and i_year % 100 != 0) or (i_year % 400 == 0)):

print("{} is a leap year.".format(i_year))

else:

print("{} is not a leap year.".format(i_year))

Step-by-step explanation:

Read year from user and assign it to variable "year".If year is completely divisible by 4 and not divisible by 100 or year is completely divisible by 400 then year is leap year otherwise year is not a leap year.

Output:

Please Enter a year:2003

2003 is not a leap year.