Question

Please help asap!! binomial factor

Answer 1

The binomial factor of the given equation is 3x-8

Solution:

We know that,

`9=3*3=3^(2)`

`64=8*8=8^(2)`

According to the formula,
`a^(2)b^(2) = (ab)^(2)`

we get,
`9x^(2)-64=3^(2)x^(2)-8^(2)=(3x)^(2)-8^(2)`

From the formula,
`a^(2)-b^(2) = (a+b) (a-b)`

Here in this step we can consider a as 3x and b as 8

On substituting the values we can simplify the above equation as,
`9x^(2)-64 = (3x+8) (3x-8)`

The factors
`9x^(2)-64` are
`(3x+8) and (3x-8)`

So, the answer is (3x-8)

Answer 2

3x - 8

Explanation:

the factors of the following equation
`9x^(2)  - 64 =` are:

`(3x - 8)(3x + 8)`

If you look the equation you can notice that you don´t have a term like -48x or 48x, so the factors must have a positive and negative sign.

Remember first you need to multiply each segment and finally add.

`(3x - 8)(3x + 8) = 9x^(2) <strong>- 24x + 24x </strong>-64` =
`9x^(2)  - 64 =`