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Y=2x^2+8x+1 find the vertex of the function below ​

Y=2x^2+8x+1 find the vertex of the function below ​
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4 votes
Y=2x^2+8x+1 find the vertex of the function below ​

User Theodore Murdock
by
8.3k points

2 Answers

2 votes
The answer would be Y= 2(x+2)^2-7
User Luca Camillo
by
8.3k points
1 vote

Answer:

The vertex- (-2, -7)

Explanation:

Correct answer

User VasiliyL
by
7.1k points
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