Question

7. What is the force of air resistance on an

2.02 80-kg sky diver who is falling downward
with an acceleration of 4.0 m/s ?
A 320 N
B 392 N
( 464 N
D. 784 N

Answer 1

C) 464 N

Step-by-step explanation:

The equation of the forces acting on the skydiver is:

`mg-R=ma`

where

(mg) is the weight of the skydiver, acting downward, with

m being the mass of the skydiver

g is the acceleration of gravity

R is the air resistance, acting upward

a is the acceleration of the skydiver

In this problem:

m = 80 kg

g = 9.8 m/s^2

a = 4.0 m/s^2

Solving the equation for R, we find the force of air resistance:

`r=mg-ma=m(g-a)=(80)(9.8-4.0)=464 N`