Answer:
a) 0.4567
b) 6 hours
Explanation:
We are given the following information the question:
The battery life follows a normal distribution with
![\mu = 9.75\\\sigma = 2.3](https://img.qammunity.org/2020/formulas/mathematics/college/1mh5dfqcd2dpv8lr0fctxon6aew3unraja.png)
Formula:
![z = \displaystyle(x-\mu)/(\sigma)](https://img.qammunity.org/2020/formulas/mathematics/college/1m0v0gwpfo3uimsb36wv1n4n8eo6nlowe2.png)
a) We have to find probability such that battery life exceeds 10 hours, that is,
P(X>10)
![P(z > \displaystyle(10 - 9.75)/(2.3)) = P(z>0.1086)\\\\= 1 - P(z \leq 0.1086)\\= 1- 0.5433\\=0.4567](https://img.qammunity.org/2020/formulas/mathematics/college/ovbxqtasreu4zn4fyh9qrc5nen8gqczcni.png)
b) We have to find battery life such that
![P(X \leq x) = 0.05\\\\P(z \leq \displaystyle(x-9.75)/(2.3)) = 0.05\\\\\displaystyle(x-9.75)/(2.3) = -1.64 \\\\x = (-1.64)(2.3) + 9.75\\x = 5.978](https://img.qammunity.org/2020/formulas/mathematics/college/46j3dfz93waubaj1eduefo0mlxp2mgh585.png)
Here, we calculated the value of z from the normal distribution table.
So, after approximately 6 hours one should plan to recharge the phone.