Question

What is the electric potential v due to the nucleus of hydrogen at a distance of 5.292×10−11 m ?

Answer 1

Answer: 27.21 V

Step-by-step explanation:

The electric potential
`V_(E)` due to a point charge is expressed as:

`V_(E)=k(q)/(r)`

Where:

`k=9(10)^(9)(Nm^(2))/(C^(2))` is the electric constant

`q=1.6(10)^(-19)C` is the electric charge of the hydrogen nucleus, which is positive

`r=5.292(10)^(-11)m` is the distance

Rewritting the equation with the known values:

`V_(E)=9(10)^(9)(Nm^(2))/(C^(2))(1.6(10)^(-19)C)/(5.292(10)^(-11)m)`

Finally:

`V_(E)=27.21 V`