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The pressure, volume, and temperature of a mole of an ideal gas are related by the equation PV = 8.31T, where P is measured in kilopascals, V in liters, and T in kelvins. Use differentials to find the approximate change in the pressure if the volume increases from 10 L to 10.6 L and the temperature decreases from 345 K to 335 K. (Note whether the change is positive or negative in your answer. Round your answer to two decimal places.)

1 Answer

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Answer:25.26 kPa

Explanation:

Given

PV=8.31T

dV=10.6-10=0.6 L

dT=335-345=-10 K


P(10)=8.31* 345

P=282.54 kPa

PV=8.31 T

differentiate

d(PV)=8.31 dT

PdV+VdP=8.31dT


282.54* 0.6+10* dP=8.31* (-10)

dP=25.26 kPa

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