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3 votes
What is the product?

(6 r minus 1)(negative 8 r minus 3)

User Antun Tun
by
5.7k points

2 Answers

3 votes

Answer:

-47r²-10r+3

Explanation:

User JAAulde
by
5.4k points
1 vote

Answer:

The required product is
-48r^2-10r+3

Explanation:

Consider the provided expression.


(6r-1)(-8r-3)

Open the parentheses.


6r\left(-8r\right)+6r\left(-3\right)+\left(-1\right)\left(-8r\right)+\left(-1\right)\left(-3\right)


-6\cdot \:8rr-6\cdot \:3r+1\cdot \:8r+1\cdot \:3


-48r^2-18r+8r+3

Add the like terms.


-48r^2-10r+3

Hence, the required product is
-48r^2-10r+3

User Alex  Glinsky
by
6.0k points