12x+7<−11 AND5x−8≥4012

Question

asked Dec 10, 2020 24.4k views

2 Answers

Lcompare · Answer 1 · 2020-12-16T14:01:53+0000

Answer:

No solution

Explanation:

Given:
12x+7<-11 and
$5x-8\geq 40$

Solve both inequality separately.

12x+7<-11 Subtraction property of inequality

12x<-11-7

12x<-18

x<-(18)/(12)

x<-(3)/(2)

and

$5x-8\geq 40$ Addition property of inequality

$5x\geq 40+8$

$5x\geq 48$

$x\geq (48)/(5)$

Hence, the solution of the compound inequality intersection of both solutions.

Please find attachment for number line solution.

No solution