Question

The vertices of the pentagon ABCDE are A(0,4), B(4,0), C(3,- 4), D(-3,- 4), E(-4,0). If the pentagon is translated 5 units down and 4

units right, the new vertices are:

a. A'(4, -1), B'(8,-5), C'(7,-9), D'(1,-9), E'(0,-5)
b. A'(4, -1), B'(8,-5), C'(7,-9), D'(1,-9), E'(1,-5)
C. A'(4, -1), B'(5,-5), C'(7,-9), D'(1,-9), E'(0,-5)
d. A'(4, -1), B'(8,-5), C'(7.-9), D'(0,-9), E'(0,-5)​

Answer 1

The answer to your question is: a. A'(4, -1), B'(8,-5), C'(7,-9), D'(1,-9), E'(0,-5)

Explanation:

pentagon ABCDE

Translated 5 units down and 4 units right

Changes Final Vertices

A (0 , 4) A (0 + 4 , 4 - 5) A (4, -1)

B (4 , 0) B (4 + 4, 0 - 5) B (8, -5)

C (3 , - 4) C (3 + 4, - 4 - 5) C (7, -9)

D (-3 , - 4) D (-3 + 4, - 4- 5) D (1, -9)

E (-4 , 0) E (-4 + 4, 0 - 5) E (0, -5)

Answer 2

A) A(4,-1)B (8,-5)C (7,-9) D(1,-9) E(0, -5)

Explanation:

To every coordinate pair, you sum 4 to each X value (since it is moving right) and substract 5 to the Y values, (because they are moving down)