1 Answer

Eggroll · Answer 1 · 2020-07-21T05:20:09+0000

Answer:

$(gof) (x) =\frac {(x+3)^{(3)/(2)}+2}{\sqrt {x + 3}}$

Explanation:

Given : Function
$f(x)=\sqrt {x+3}$ and
g(x)=x^2+(2)/(x)

To find : The value of (gof)(x) ?

Solution :

We know that,

(gof) (x) = g(f (x))

Substituting the values,

$(gof) (x) = g(\sqrt {x+3})$

$(gof) (x) =(\sqrt {x + 3})^2+ \frac {2} {\sqrt {x + 3}}$

$(gof) (x) =(x + 3) + \frac {2} {\sqrt {x + 3}}$

$(gof) (x) =\frac {(x+3)(\sqrt {x + 3})+2} {\sqrt {x + 3}}$

$(gof) (x) =\frac {(x+3)^{(3)/(2)}+2}{\sqrt {x + 3}}$

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