Question

If the electric field strength is measured as 150 V/m across two plates that are placed 3.5 cm apart, what is the potential across the plates?

Answer 1

5.3

150 * .035=5.3

Step-by-step explanation:

Answer 2

The potential across the plates is 5.25 V

Step-by-step explanation:

Let us assume that the Electric field is E; Force is F; Unit charge is q, the Electric potential is V and distance is d.

Here E = 150 v/m and d = 3.5 cm = 0.035 m

Now we know that,

Electric Field E
`= (Force)/(Unit Charge) = (F)/(q)` ----- [1]

`Work W = Force * distance = (F * d)` ----- [2]

`Electric potential V = (work)/(unit charge) = (W)/(q)`

So,
`V = (W)/(q) = {F* d}{q}`

`=>(F)/(q)* d = (E * d) = (150*0.035) V = 5.25V`

Thus, The potential across the plates is 5.25 V