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URGENT A force of 35 N is used to stretch a spring 15 cm beyond its normal length. What is the increase in the spring's energy?
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URGENT

A force of 35 N is used to stretch a spring 15 cm beyond its normal length. What is the
increase in the spring's energy?

User Peter McEvoy
by
4.0k points

1 Answer

9 votes

Answer:

5.25 J

Step-by-step explanation:

W = PE = (f)(x)

PE = 35N*0.15m

PE = 5.25 N*m

1 N*m = 1 J

PE = 5.25 J

User Nemec
by
4.8k points
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