Question

Given the function ƒ(x) = 3x3 + 7x2 + 5x, find ƒ(−3).

Answer 1

-33

Explanation:

To solve this problem

substitute -3 for x

f(-3)= 3(-3^3) + 7(-3)^2 +5(-3)

f(-3) = 3(-27) + 7(9) -15

f(-3) = -81 +63 - 15

f(-3) = -18 -15

f(-3) = -33

Answer 2

`f(-3)=-33`

Explanation:

Function :
`f(x) = 3x^3 + 7x^2 + 5x`

We are supposed to find
`f(-3)`

Substitute the value of x = -3 in given function

`f(x) = 3x^3 + 7x^2 + 5x`

`f(x) = 3(-3)^3 + 7(-3)^2 + 5(-3)`

`f(x) = 3(-27) + 7(9) + 5(-3)`

`f(x) = -33`

Hence
`f(-3)=-33`