Question

The gene D controls wing shape in flies and has two alleles: D is wild-type and dominant, and d is recessive and causes flies to have downward pointed wings. The gene E controls eye development and also has two alleles: E is wild-type and dominant, and e is recessive and causes the flies to have small eyes. The two genes are located on the same chromosome. A pure-breeding fly with normal wings and small eyes was crossed with a pure-breeding fly with downward wings and normal eyes. All of the F1 progeny had a wild-type phenotype. The recombination frequency between the two genes is 14%. If an F1 individual was test crossed, what percentage of the progeny would you expect to have the WT phenotype?43%7%28%14%86%

Answer 1

7 % progeny will show wild type phenotype

Step-by-step explanation:

Parent 1: Normal wings and small eyes : DDee

Parent 2 : Downward wings and normal eyes : ddEE

DDee X ddEE = DdEe ( All have normal wings and normal eyes )

When a F1 individual is test crossed:

DdEe X ddee =

De/de = Parental

dE/de = Parental

DE/de = Recombinant

de/de = Recombinant

Recombination frequency between the two genes is 14% hence DE/de and de/de will each have 7% frequency. Since DE/de ( DdEe ) will give wild type phenotype, it means that 7% progeny will have wild type phenotype.