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Roll a dice twice. What are the chances you'll get a 2 and a 4?

Examples: 2-9 (Chance of 2 to 9) , 5-13 (Chance of 5 to 13)

User Exifers
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2 Answers

3 votes

Answer: The required probability is
(1)/(36).[\tex]</p><p></p><p><strong>Step-by-step explanation: &nbsp;</strong>Given that a dice is rolled twice.</p><p>We are to find the<strong> probability that we will get a 2 and a 4.</strong></p><p>Let A and B denote the events of getting a 2 and a 4 respectively.</p><p>The sample space, S = {1, 2, 3, 4, 5, 6} &nbsp;</p><p>⇒ <strong>n(S) = 6.</strong></p><p>Also, <strong>A = {2} &nbsp;⇒ &nbsp;n(A) = 1 &nbsp; &nbsp; and &nbsp; &nbsp; &nbsp;B = {4} &nbsp; ⇒ &nbsp; n(B) = 1.</strong></p><p>Then,<strong> the probabilities of events A and B are given by</strong></p><p>[tex]P(A)=(n(A))/(n(S))=(1)/(6),\\\\\\P(B)=(n(B))/(n(S))=(1)/(6).

Since the events A and B are independent of each other, so the probability that we will get a 2 and a 4 is given by


P(A\cap B)=P(A)* P(B)=(1)/(6)*(1)/(6)=(1)/(36).

Thus, the required probability is [tex]\dfrac{1}{36}.[\tex]

User Pouria Almassi
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5.3k points
3 votes

Answer:


(1)/(3)

Explanation:

In probability, "AND" means "MULTIPLICATION" and "OR" means "ADDITION".

Here we want "AND", so we need to multiply individual probability.

Probability of getting a 2 in first roll is 1/6 [one 2 and 6 numbers in total]

Also

Probability of getting a 4 in 2nd roll is 1/6 [one 4 and 6 numbers in total]

Hence, P (2 and 4) = 1/6 + 1/6 = 2/6 = 1/3

User Vaclav Pech
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