Answer:
v1 =1.0852 m^3/kg
T2=99.60°C
x(2)=64%
Step-by-step explanation:
For the initial condition we have superheated steam at 200kPa and 200°C from the thermodynamics tables we get the specific volume for this condition
We can locate this point in the T-v diagram (see picture) point 1.
Since both the outlet and inlet valve are closed, we can assume that the volume in the system is constant during the process.
For the second condition we know the pressure (100 KPa) and the specific volume (1.0852 m^3/kg) because this is constant.
The conditions for saturation at 100 KPa are:
specific volume for the saturated vapor.
specific volume for the saturated liquid.
Since the specific volume for our condition is among the specific volume for saturated liquid and saturated vapor. We are in the saturated region, so the temperature for the final condition will be 99.60°C.
The quality (x) can be estimated considering that:
Clearing for x we have:
So:
The quality is 64% in the final condition.