Question

A bus is moving at a speed of 60 km/h. How far from a bus stop should the bus start to slow down so that the passengers feel comfortable (a comfortable acceleration is 1.2 m/s2)?

Answer 1

116.2 m

Step-by-step explanation:

We can solve the problem by using the following SUVAT equation:

`v^2-u^2=2ad`

where

v is the final velocity

u is the initial velocity

a is the acceleration

d is the stopping distance

In this problem:

v = 0 (the bus comes to a stop)

`u=60 km/h \cdot (1000)/(3600)=16.7 m/s` is the initial velocity

`a=-1.2 m/s^2` is the deceleration

d is the stopping distance

Solving for d,

`d=(v^2-u^2)/(2a)=(0-(16.7)^2)/(2(-1.2))=116.2 m`