Question

In an experiment, a student estimates the acceleration due to gravity is 9.31 m/s2. The actual value is 9.8 m/s2. What is the student's percent error

Answer 1

The percent error of student is -5 %.

Step-by-step explanation:

Given data:

measured value = 9.31 m/s²

actual value = 9.8 m/s²

percent error = ?

Formula:

% error = (measured value - actual value / actual value ) × 100

% error = (9.31 m/s² - 9.8 m/s² / 9.8 m/s²) × 100

% error = (-0.49 m/s² / 9.8 m/s²) × 100

% error = -0.05 × 100

% error = -5

Answer 2

The answer is 5% error rate

Step-by-step explanation:

Hello!

Let's solve this!

The data we have are:

Actual Gravity = 9.8m / s2

measured severity = 9.31m / s2

The% error is measured with the following formula:

% error = ((actual value-measured value) / actual value) * 100

% error = (9.8-9.31) /9.8) * 100

% error = 5%

The answer is 5% error rate