Answer:
a)Cycle time = 2.37 min
b)Numbers of workers =21
c)Stations on the line =24
Step-by-step explanation:
Given that
Total work content time(TWC) = 50 min
Production rate Rp= 24 units/hr
manning level will be close =1.5
Line balancing efficiency =0.94
a)
Cycle time


Cycle time = 2.37 min
b)
Numbers of workers ,W


W= 21
Numbers of workers =21
c)
Stations on the line(n)
Lets find service time Ts
Ts = Cycle time - Time for repositioning
Ts = Tc- Tr
Ts= 2.37 - 9/ 60 min
Ts= 2.22 min
We know that efficiency


n=23.94 ⇒n=24
n=24
Stations on the line =24