Answer:
200.1kJ/Kg
Step-by-step explanation:
To solve this problem we must apply the first law of thermodynamics, which indicates that the energy that enters a system is the same that must come out, resulting in the following equation
q=cp(T2-T1)
where
q= heat per unit mass
cp=specific heat for air=1.005KJ/(kgK)
Specific heat is a property of air that indicates how much the air temperature rises per unit of thermal energy
T2=temperature in state 2=500k
T1=temperature in state 1=300k
q=1.005(500-300K)=200.1kJ/Kg