Answer:
#include <bits/stdc++.h>
using namespace std;
int main() {
int a[10],sum=0,max=INT_MIN,min=INT_MAX;
cout<<"Enter 10 integers"<<endl;
for(int i=0;i<10;i++)//taking input..
{
cin>>a[i];
}
for(int i=0;i<10;i++)//loop for finding the sum,maximum and minimum.
{
sum=sum+a[i];//calculating sum..
if(a[i]>max)//condition for maximum..
{
max=a[i];
}
if(a[i]<min)//condition for minimum..
{
min=a[i];
}
}
cout<<"The sum of the integers is "<<sum<<endl
<<"The maximum integer is "<<max
<<endl<<"The minimum integer is "<<min<<endl; //printing the sum,maximum,minimum.
return 0;
}
Output:-
Enter 10 integers
2 54 8 56 2 1 78 20 90 125
The sum of the integers is 436
The maximum integer is 125
The minimum integer is 1
Step-by-step explanation:
I have taken an integer array of size 10 and initialized sum with 0 max with minimum value possible and min with maximum value possible.
First loop is to take input from the user.
The next loop find the sum,maximum and minimum.
Then printing the sum,maximum and minimum.