Question

A 4 standard type L copper tube conveys propyl alcohol at 151/s. The pipe is laid out horizontally. It is 60 îm long. Calculáte the pressure drop

Answer 1

P₁ - P₂ = 17.18 MPa

Step-by-step explanation:

Pressure drop along the horizontal pipe = P₁ - P₂

=
`(128\mu L Q)/(\piD^4)`

length of the pipe = 60 m

flow rate of propyl alcohol = 15 l/s

= 0.015 m³/s (∵ 1 l/s = 10⁻³ m³/s)

for 4 standard pipe,

diameter of the pipe = 8 mm = 0.008 m

viscosity of propyl alcohol = 0.00192 N-s/m²

`P_1-P_2 =(128\mu L Q)/(\piD^4)`

=
`(128* 0.00192 * 60 * 0.015)/(\pi* 0.008^4)`

P₁ - P₂ = 17.18 MPa

hence, pressure drop is equal to 17.18 MPa