Answer:
![1101*0110=1001110](https://img.qammunity.org/2020/formulas/computers-and-technology/college/zmpdl35ukjqrdfocsa61kxw1ez6gpc9uwo.png)
Step-by-step explanation:
First, multiply like if you were multiplying normally, but keep in mind this:
1*0=0
0*0=0
0*1=0
1*1=1
You should get this result:
1 1 0 1
0 1 1 0 x
-------------------------
0 0 0 0
1 1 0 1 0
1 1 0 1 0 0
0 0 0 0 0 0 0
Now sum these terms:
0 0 0 0
1 1 0 1 0
1 1 0 1 0 0 +
0 0 0 0 0 0 0
-------------------------
The first column, from the right:
0+0+0+0=0
The second column, from the right:
0+1+0+0=1
The third column, from the right:
0+0+1+0=1
The fourth column, from the right:
1+1+0=2,
2 in binary is 0010, so we put 0 and we carry the 1
The fith column from the right:
(because we carried the 1 from the previous sum)
1+1+0=2, so the same, we put 0 and we carry the 1
And finally the sixth column, from the right:
(because we carried the 1 from the previous sum)
1+0=1
So:
1 1 0 1
0 1 1 0 x
-------------------------
0 0 0 0
1 1 0 1 0
1 1 0 1 0 0 +
0 0 0 0 0 0 0
-------------------------
1 0 0 1 1 1 0
Let's verify the results:
![1101=2^(3) +2^(2) +0 +2^(0) =8+4+0+1=13](https://img.qammunity.org/2020/formulas/computers-and-technology/college/j6k5k56k6nnthw8ity6fv4qblqy3rrfgi7.png)
![0110=0+2^(2) +2^(1) +0 =0+4+2+0=6](https://img.qammunity.org/2020/formulas/computers-and-technology/college/87qmye6c2i7c4i78lhg67ih4l6rb1iewtr.png)
![13*6=78](https://img.qammunity.org/2020/formulas/computers-and-technology/college/trvjgnbylu3m5po9d2hpbkne6qvmqc59i6.png)
![1001110=2^(6) +0+0+2^(3) +2^(2) +2^(1) +0=64+0+0+8+4+2+0=78](https://img.qammunity.org/2020/formulas/computers-and-technology/college/18xcdue9jgayqqqqrmu0c2x37mqyjrvrx0.png)