Question

A bowling ball has an initial momentum of +30 kg m/s and hits a stationary bowling pin. After the collision, the bowling ball leaves with a momentum of +13 kg • m/s

Answer 1

+17 kg m/s

Step-by-step explanation:

Question is missing. Found it on google:

"What is the magnitude of the final momentum of the bowling pin if it has a mass of 1.5 kg?"

Solution:

we can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the system must be conserved, so we can write:

`p_i = p_f\\p_b+p_p=p_b'+p_p'`

where

`p_b = +30 kg m/s` is the momentum of the ball before the collision

`p_p = 0` is the momentum of the pin before the collision (zero because the pin is stationary)

`p_b' = +13 kg m/s` is the momentum of the ball after the collision

`p_p'` is the momentum of the pin after the collision

Solving the equation for
`p_p'`, we find:

`p_p' = p_b + p_p - p_b' = +30 +0 -(+13)=+17 kg m/s`