Question

A mass of 0.3 kg is suspended from a spring of stiffness 0.4 N/mm. The damping is 3.286335345 kg/s. What is the undamped natural frequency of the system in Hz?

Answer 1

f=5.81 Hz

Step-by-step explanation:

Given that

m= 0.3 kg

K= 0.4 N/mm

K= 400 N/m

C= 3.28

We know that undamped natural frequency given as

`\omega= \sqrt{(K)/(m)}`

Now by putting the values

`\omega= \sqrt{(K)/(m)}`

`\omega= \sqrt{(400)/(0.3)}`

ω = 36.51 rad/s

We know that

ω = 2 π f

36.51 = 2 x π x f

f=5.81 Hz

So the undamped natural frequency is 5.81 Hz.