Answer:
μ = 0.136
Step-by-step explanation:
given,
velocity of the car = 20 m/s
radius of the track = 300 m
mass of the car = 2000 kg
centrifugal force
![F_c = (mv^2)/(r)](https://img.qammunity.org/2020/formulas/engineering/college/71odyquynl56hix6yckwq9t1ye4mnt6hbj.png)
![F_c = (2000* 20^2)/(300)](https://img.qammunity.org/2020/formulas/engineering/college/oen8o1ghh1wntilmrua2csgiwjbedspnz3.png)
F c = 2666. 67 N
F f= μ N
F f = μ m g
2666.67 = μ × 2000 × 9.8
μ = 0.136
so, the minimum coefficient of friction between road surface and car tyre is equal to μ = 0.136