Question

Calculate the potential energy in kJ of a human body (70 kg) possesses on top of the Empire State Building (1,250 ft tall).

Answer 1

Potential energy = 261.633 kJ

Step-by-step explanation:

The potential energy is the energy stored in an object due to its position above Earth's surface.

The potential energy formula is :

`E_(p) =m.g.h`

Where
`E_(p)` is the potential energy

m is the object mass

g is the gravity

and h is the height referred to a comparison plane

We start by converting the height in feets to meters

`h=1250ft=1250ft.(0.3048m)/(1ft) =381m\\h=381m`

`m=70kg`

and

`g=9.81(m)/(s^(2) )`

`E_(p) =(70kg).(9.81(m)/(s^(2) ) )(381m)=261632.7 kg.(m)/(s^(2) ) .m`

Where

`kg.(m)/(s^(2) ) =N`

N is Newton

`N.m=J`

J is Joule. Joule is the energy unit

`E_(p) =261632.7 J`

We divide it by 1000 to obtain kJ

`261632.7 (J)/(1000) =261.633 kJ`