Answer:
x = 4 , y = 0
Explanation:
Solve the following system:
{3 x - y = 12 | (equation 1)
4 x - 5 y = 16 | (equation 2)
Swap equation 1 with equation 2:
{4 x - 5 y = 16 | (equation 1)
3 x - y = 12 | (equation 2)
Subtract 3/4 × (equation 1) from equation 2:
{4 x - 5 y = 16 | (equation 1)
0 x+(11 y)/4 = 0 | (equation 2)
Multiply equation 2 by 4/11:
{4 x - 5 y = 16 | (equation 1)
0 x+y = 0 | (equation 2)
Add 5 × (equation 2) to equation 1:
{4 x+0 y = 16 | (equation 1)
0 x+y = 0 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 4 | (equation 1)
0 x+y = 0 | (equation 2)
Collect results:
Answer: {x = 4 , y = 0