Question

Input 10 integers and display the following:

a. the sum of even numbers.
b. the sum of odd numbers.
c. the largest integer
d. the smallest integer
e. the total count of even numbers
f. the total count of odd numbers.

Answer 1

// code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

// variables

int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;

int largest=INT_MIN;

int smallest=INT_MAX;

int n;

cout<<"Enter 10 Integers:";

// read 10 Integers

for(int a=0;a<10;a++)

{

cin>>n;

// find largest

if(n>largest)

largest=n;

// find smallest

if(n<smallest)

smallest=n;

// if input is even

if(n%2==0)

{

// sum of even

sum_even+=n;

// even count

eve_count++;

}

else

{

// sum of odd

sum_odd+=n;

// odd count

odd_count++;

}

}

// print sum of even

cout<<"Sum of all even numbers is: "<<sum_even<<endl;

// print sum of odd

cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;

// print largest

cout<<"largest Integer is: "<<largest<<endl;

// print smallest

cout<<"smallest Integer is: "<<smallest<<endl;

// print even count

cout<<"count of even number is: "<<eve_count<<endl;

// print odd cout

cout<<"count of odd number is: "<<odd_count<<endl;

return 0;

}

Step-by-step explanation:

Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.

Output:

Enter 10 Integers:1 3 4 2 10 11 12 44 5 20

Sum of all even numbers is: 92

Sum of all odd numbers is: 20

largest Integer is: 44

smallest Integer is: 1

count of even number is: 6

count of odd number is: 4