Question

Air friction damps a tuning fork so the amplitude decreases by 1/10 per second. Resonances] 10 Hz. what % chnge in frequency results?

Answer 1

The percentage change in frequency is 10%.

Step-by-step explanation:

Given that,

Amplitude decreases by 1/10 per second.

Resonance = 10 Hz

We need to calculate the change in frequency

Using formula of change in frequency

`\Delta f=\Delta A* R`

Put the value into the formula

`\Delta f=(1)/(10)*10`

`\Delta f=1\ Hz`

We need to calculate the resonant frequency

Using formula of resonant frequency

`f_(r)=R-\Delta f`

Put the value into the formula

`f_(r)=10-1`

`f_(r)=9\ Hz`

We need to calculate the percentage change in frequency

Using formula of percentage change in frequency

`f=(10-9)/(10)`

`f=10\%`

Hence, The percentage change in frequency is 10%.