163k views
1 vote
Find three solutions to the linear equation 4x+y=20 ​

User Lovelace
by
7.8k points

1 Answer

10 votes

Answer:


(0,20),(1,16),(2,12)

Explanation:


We\ are\ provided\ with\ the\ equation:\\4x+y=20\\In\ order,\ to\ find\ solutions\ to\ a\ linear\ equation\ in\ two\ variables,\ we\\ usually\ substitute\ a\ value\ to\ either\ the\ abscissa or\ the\ ordinate\ to\ get\\ the\ corresponding\ ordinate\ or\ the\ abscissa.\\Hence,\\Here,


Let's\ plug\ in\ simpler\ value's\ of\ 0,1,2\ as\ the\ x-co-ordinate\ to\ obtain\ it's\\ y-coordinate.\\Hence,\\Coming\ back\ to\ our\ equation:4x+y=20\\Substituting\ x=0,\\4*(0)+y=20\\y=20\\Hence,\\x=0,y=20\ or\ (0,20)\ is\ a\ solution\ of\ the\ equation.


Substituting\ x=1,\\4*(1)+y=20\\4+y=20\\y=20-4=16\\Hence,\\x=1,y=16\ or\ (1,16)\ is\ also\ a\ solution\ of\ the\ equation.


Substituting\ x=2,\\4*(2)+y=20\\8+y=20\\y=20-8=12\\ Hence,\\x=2,y=12\ or\ (2,12)\ is\ a\ solution\ of\ the\ equation\ too.


Hence,\ collecting\ all\ the\ solutions\ of\ the\ equations:\\(0,20),(1,16),(2,12)\ are\ all\ solutions\ of\ the\ given\ equation.\\

User Kninnug
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories