Answer : The volume of a sample of 4.00 mol of copper is
![28.5cm^3](https://img.qammunity.org/2020/formulas/physics/college/xq33b5b62tdo6nj0lc40k3rrov7lg32x7k.png)
Explanation :
First we have to calculate the mass of copper.
![\text{ Mass of copper}=\text{ Moles of copper}* \text{ Molar mass of copper}](https://img.qammunity.org/2020/formulas/physics/college/f6ks0eeqkkupsjtsjp6bf74s7bb4rbpo5b.png)
![\text{ Mass of copper}=(4.00moles)* (63.5g/mole)=254g](https://img.qammunity.org/2020/formulas/physics/college/hclthv5hna67tnfvrv1hwszmw8seh6bjwe.png)
Now we have to calculate the volume of copper.
Formula used :
![Density=(Mass)/(Volume)](https://img.qammunity.org/2020/formulas/chemistry/middle-school/hzknnknzlihjnnp7o4jwkew5bpcuhffxxx.png)
Now put all the given values in this formula, we get:
![8.92* 10^3kg/m^3=(254g)/(Volume)](https://img.qammunity.org/2020/formulas/physics/college/hpdsd9yjfa913vrstylb1mi2n36qhilqjt.png)
![Volume=(254g)/(8.92* 10^3kg/m^3)=2.85* 10^(-2)L=2.85* 10^(-2)* 10^3cm^3=28.5cm^3](https://img.qammunity.org/2020/formulas/physics/college/6cu74np9oiagjexq7dpfda2ak086dvm5ia.png)
Conversion used :
![1kg/m^3=1g/L\\\\1L=10^3cm^3](https://img.qammunity.org/2020/formulas/physics/college/lutx7xpugpc8cs6deaxioh1yjd0ilgd9kh.png)
Therefore, the volume of a sample of 4.00 mol of copper is
![28.5cm^3](https://img.qammunity.org/2020/formulas/physics/college/xq33b5b62tdo6nj0lc40k3rrov7lg32x7k.png)