Answer:0.846 c, 0
Step-by-step explanation:
Giving
Body is initially moving with 0.5 c
The velocity of the fragment which is moving with velocity of 0.6 c is appears to be move with velocity of
![v_0=(u+v)/(1+(uv)/(c^2))](https://img.qammunity.org/2020/formulas/physics/college/stjl9cmh9slt3uitgc7api4rjt8x44th5v.png)
![v_0=(0.5c+0.6c)/(1+(0.5c\cdot 0.6c)/(c^2))](https://img.qammunity.org/2020/formulas/physics/college/343lutzjp1ffoafvv1fqy7xiajy953o287.png)
![v_0=(1.1c)/(1.3)=0.846 c](https://img.qammunity.org/2020/formulas/physics/college/y4jjb0f81bzeq187pg6wp5b8dh8qzwz5m3.png)
And the velocity of particle moving in opposite direction with velocity 0.5 c
![v_0=(u+v)/(1+(uv)/(c^2))](https://img.qammunity.org/2020/formulas/physics/college/stjl9cmh9slt3uitgc7api4rjt8x44th5v.png)
![v_0(-0.5c+0.5c)/(1+(0.5c* (-0.5c))/(c^2))=0](https://img.qammunity.org/2020/formulas/physics/college/qpm9qipya07gmmciyqcoxu2ndg2jzyoppi.png)