Question

The electric field at the distance of 3.5 meters from an infinite wall of charges is 125 N/C. What is the magnitude of the electric field 1.5 meters from the wall?

Answer 1

Step-by-step explanation:

It is given that,

Distance, r = 3.5 m

Electric field due to an infinite wall of charges, E = 125 N/C

We need to find the electric field 1.5 meters from the wall, r' = 1.5 m. Let it is equal to E'. For an infinite wall of charge the electric field is given by :

`E=(\lambda)/(2\pi \epsilon_o r)`

It is clear that the electric field is inversely proportional to the distance. So,

`(E)/(E')=(r')/(r)`

`E'=(Er)/(r')`

`E'=(125* 3.5)/(1.5)`

E' = 291.67 N/C

So, the magnitude of the electric field 1.5 meters from the wall is 291.67 N/C. Hence, this is the required solution.