Question

A jet fighter plane is launched from a catapult on an airaraft carrier. It reaches a speed of 42 mis at the end of the catapult, and this requires 2.0s. Assuming the acceleration is O 63 m O 24 m O 84 m O 42 m O 16 m

Answer 1

s = 42 meters

Step-by-step explanation:

Initial speed of the jet, u = 0

Final speed of the jet, v = 42 m/s

Time taken, t = 2 s

Let a is the acceleration of the jet. It can be calculated using equation of kinematics as :

`a=(v-u)/(t)`

`a=(42\ m/s)/(2\ s)`

`a=21\ m/s^2`

It is assumed that the acceleration of the jet is constant. We can find the length of the catapult. It is given by s.

`s=ut+(1)/(2)at^2`

`s=(1)/(2)* 21* (2)^2`

s = 42 meters

So, the length of the catapult is 42 meters. Hence, this is the required solution.