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A ball is dropped from the top of a 77 m building. With what speed does the ball hit the ground? _________ m/s

User Abbott
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1 Answer

1 vote

Answer:

38.87 m/s

Step-by-step explanation:

Given that the ball is dropped from a height = 77 m

u = 0 m/s

s = 77 m

a = g = 9.81 m/s²

Applying the expression as:


v^2-u^2=2as

Applying values as:


v^2-u^2=2as\\\Rightarrow v=√(2as+u^2)\\\Rightarrow v=√(2* 9.81* 77+0^2)\\\Rightarrow v=38.87\ m/s

The speed with which the ball hit the ground = 38.87 m/s

User Gurmanjot Singh
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6.2k points